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Lapatulllka [165]
3 years ago
12

HELP GIVING BRAINLY TO CORRECT ANSWER!! The distance between the two points is given. Show the work that gives you the answer. B

e specific.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:

The work is on the picture

sorry was not letting write the work here

Step-by-step explanation:

Download pdf
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What is the answer to 4 divided by 50.38 (long division). PLEASE SHOW YOUR WORK!
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There you go, help this helps!

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Draw the image of ∆ABC under the dilation with scale factor 4 and center of dilation (-3, -4).
castortr0y [4]

Answer:

ABC

Step-by-step explanation:

7 0
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What is the factorization of 49b2 − 81?
worty [1.4K]

Step-by-step explanation:

The factorisation of 49b^2 - 81 is (7b - 9)(7b + 9). This is because 49 and 81 are the squares of 7 and 9 respectively, so these must be multiplied together. b^2 is b x b. Finally, it must be -9 and +9 to make -81, because when the signs are the same the result is a positive number

8 0
3 years ago
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Sketch the following to help answer the question. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals
BigorU [14]

Kite has two pairs of adjacant sides equal. So side QR is either equal to QT or to RS. If side QR equals QT. So then QT = 17

Diagonals in kite cross each other at right angle. So in right trinagle QPT, QT is hypotenuse. Now if QT = 17, and we are given PT = 25. We cannot have hypotenuse smaller than other side. So QR cannot be equal to side QT. So QR has to be equal to other adjacent side RS. So we will have kite QRST as shown in figure.

So RS = 17. If side QR and RS are equal so diagonal RT will bisect(divide in half) diagonal QS then.

AS QS = 30 (given) so PS = PQ = \frac{30}{2} = 15

Now in right triangle RPS we have

RS = 17

PS = 15

We have to find other side RP.

For that we will use pythagorean formula

c^{2} = a^{2} + b^{2} where c is the hypotenuse side and a and b are the other two sides of triangle

So in right triangle RPS we will have hypotenuse as RS (opposite ot right angle) so we will have

RS^{2} = PS^{2} + RP^{2}

Now plug values in equation. Plug 17 in RS place, 15 in PS place and RP is known so let that be x

17^{2} =  x^{2} + 15^{2}

289 = x^{2} + 225

now solve for x as shown

289 - 225 = x^{2} + 225 - 225

64 = x^{2}

\sqrt{64} = \sqrt{x^2}

8 = x

So RP = 8

Also we are given PT = 25

So diagonal RT= RP + PT = 8 + 25 = 33m

Area of kite is given by formula

\frac{pq}{2} where p and q are the diagonals in kite

Here we have digonal RT= 33m and diagonal QS = 30m

So area = \frac{33 \times 30}{2} = \frac{990}{2} =495 m^{2}

so final answer for area of kite is 495 m^{2}

4 0
3 years ago
Please please help idk what to do
KIM [24]
2 is the answer, it goes up 2 and over 1. Keep in mind rise over run
4 0
3 years ago
Read 2 more answers
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