Answer:
a.Qualitative and Continuous
Step-by-step explanation:
Answer:
The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Middle 90%
Between the 50 - (90/2) = 5th percentile to the 50 + (90/2) = 95th percentile.
5th percentile:
X when Z has a pvalue of 0.05. So X when Z = -1.645.
95th percentile:
X when Z has a pvalue of 0.95. So X when Z = 1.645.
The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758
Step-by-step explanation:
total ratio is 5
first find the total amount
bob's ratio is 2/5
so 2/5 ×total amount=8 pounds
0.4 ×total amount=8 pounds
total amount=8/0.4=20 pounds
so chris receives: 20-8=12 pounds
Y = kx as y and x are directly proportional
6 = 10k
k = 0.6
y = 0.6x
18 = 0.6x
x = 30
Answer:
-12y + 20
Step-by-step explanation:
First, you simplify each term:
apply the distributive property:
4 - 5y - 2 (3.5y) - 2 x -8
Multiply 3.5 by -2:
4 - 5y - 2 (3.5y) - 2 x -8
Multiply -2 by -8:
4 - 5y - 7y +16
Next, we simplify by adding terms:
Add 4 + 16:
-5y - 7y + 20
Subtract 7y from 5y:
-12y + 20
Hence the simplified form is -12y + 20