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3 years ago

Answer and question is in the pictures.

Mathematics

1 answer:

bogdanovich [222]3 years ago

7 0

Answer:

< - 52, 48 > and 70.77

Step-by-step explanation:

2v - 6u

= 2<- 11, 3 > - 6 < 5, - 7 >

= < - 22, 6 > - < 30, - 42 >

= < - 52, 48 >

| 2v - 6u | = $\sqrt{(-52)^2+(48)^2}$ = $\sqrt{5008}$ = 70.77

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If x = 4 units, y = 5 units, and h = 4 units, find the area of the rhombus shown above using decomposition.

QveST [7]

A. 36 square units
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4 0

2 years ago

Find (f+g)(x).

kaheart [24]

Answer:

(f+g)(x) = x^3 - 3x + 2

Step-by-step explanation:

Find (f+g)(x) by adding together f(x) = -3x + 2 and g(x) = x^3:

(f+g)(x) = -3x + 2 + x^3, or, in standard form,

(f+g)(x) = x^3 - 3x + 2

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2 years ago

(a2 − 6) and (a2 + 4) are the factors of

sleet_krkn [62]

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8 0

3 years ago

Tomas wrote the equation y = 3x +y equals 3 x plus StartFraction 3 over 4 EndFraction.. When Sandra wrote her equation, they dis

BaLLatris [955]

Answer:

$-6x+2y=\frac{3}{2}$

Step-by-step explanation:

The equation Thomas wrote is:

$y=3x+\frac{3}{4}$ ...equation 1

Let us subtract 3x from both sides to get:

$-3x+y=\frac{3}{4}$

We now multiply through by 2 to get:

$-6x+2y=\frac{3}{2}$ ....equation 2

We can see that equation one and two are equivalent and hence have the same solution.

Therefore Sandra's equation is $-6x+2y=\frac{3}{2}$

6 0

3 years ago

Read 2 more answers

Five years from now, the sum of the ages of a women and her daughter will be 40 years. The difference in their present age is 24

CaHeK987 [17]

Answer:

Her daughter is 3 years old now.

Step-by-step explanation:

Given:

Five years from now, the sum of the ages of a women and her daughter will be 40 years.

The difference in their present age is 24 years.

Now, to find how old is her daughter now.

Let the age of daughter be $x\ years$ .

And the age of mother be $y\ years$ .

According to question:

$(x+5)+(y+5)=40$

⇒ $x+y+10=40$

Subtracting both sides by 10 we get:

⇒ $x+y=30$

⇒ $x=30-y$ ............( 1 )

Now, as given in question:

The difference in their present ages is 24 years.

$x-y=24$

Putting the equation ( 1 ) in the place of $x$ we get:

⇒ $(30-y)-y=24$

⇒ $30-2y=24$

Moving variable on one side and the numbers on the other:

⇒ $30+24=2y$

⇒ $54=2y$

Dividing both sides by 2 we get:

⇒ $27=y$

So, the age of the mother is 27 years.

Now, putting the value of $y$ in equation( 1 ) we get:

$x=30-27$

⇒ $x=3$

The age of daughter is 3 years.

Therefore, her daughter is 3 years old now.

4 0

3 years ago