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MrRissso [65]
3 years ago
7

Consider what fact-finding techniques you would use to identify the important facts needed to develop a database system. Please

consider at least 4 methods and compare the advantages and the disadvantages of each method
Computers and Technology
1 answer:
8090 [49]3 years ago
3 0

Answer:

Examples of Fact-finding techniques includes:

  1. Prototyping
  2. Questionnaires
  3. Research and sites visit
  4. Interviews

Explanation:

It is important to note that a database system is a tool that allows users to define, create, maintain, and control access to a collection of logically related data and description of these data, designed to meet the information needs of an organization.

<u>Prototyping </u>

<em>Advantage:</em>  enables testing and understanding of the system in advance before final implementation of solution, while requiring less time for research.

<em>Disadvantage:</em> Training and Development cost consumes resources.

<u>Research and site visit </u>

<em>Advantage :</em> better time management if the problem has been researched upon before.

<em>Disadvantage:</em> appropriate permission is often needed before using research materials.

<u> Questionnaires </u>

<em>Advantage: </em>This technique is not expensive, and responses can be calculated and analysed quickly.

<em>Disadvantage:</em> There may be Incomplete answers received from users and body language of user cannot be observed.

<u>Interviews</u>

<em>Advantage:</em> The body language of interviewees is been perceived.

<em> Disadvantage: </em>Interviewing is time consuming and costly.

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guajiro [1.7K]
You didn’t explain your question correctly so I can’t help you
3 0
2 years ago
You are using a crimper to attach an RJ-45 connector to a Cat 6 UTP cable. You need to use the T568A standard to connect the ind
tino4ka555 [31]

Answer: The green and white wire (g) should be in pin 1 according to T568A standard.

Explanation: Please see diagram attached.

(source of image: http://www.fiber-optic-components.com/rj45-connector-used-in-ethernet-connectivity.html)

3 0
2 years ago
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
3 years ago
Electronic résumés have an attractive, highly formatted appearance. please select the best answer from the choices provided t f
Len [333]

An electronic resume can carry so much data about the person, and it includes images also. Then the statement is true.

<h3>What is an electronic resume?</h3>

An electronic resume is termed as a resume that is read by a computer program that summarizes the information of each person.

The electronic resume has the data such as their parent name, education, skills, job experience, hobbies, languages, and so on.

Thus, the photo of the document about the project or internship that has been done in the past can be given on the electronic resume by uploading the certificate on the computer system along with the resume.

For example, in companies like Linkedin, and so on there are many companies that ask about the person before creating an account.

More about the electronic resume link is given below.

brainly.com/question/2798964

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2 years ago
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Antivirus software products require that you update _____ on a regular basis
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Operating System, as far as I know @[email protected]
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