I believe that the option among these that is an Internet job search "do" is to pay attention to all directions before responding to job postings. You should be aware that you are never safe on the Internet, so be very careful.
Risk assessment should cover all the processes and systems included in an organization. This means this includes also the technical support including <span>firewalls, secure operating systems and networks, and antivirus protection. Risk is always present and inevitable in every way so it is important to anticipate and make early detections to counter with actions as soon as one can.</span>
Answer:
Hence the correct option is option a) define both structures and then create a data member of the nested structure type within the other structure.
Explanation:
To make Address nested to Employee, we've to define Address structure before and out of doors Employee structure and make an object of Address structure inside Employee structure.
For example, we may need to store the address of an entity employee in a structure.
Answer:
Please check the explanation
Explanation:
That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.
#include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "****WELCOME TO THE GUESS THE NUMBER GAME!****\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); }
Answer: There are several types of jobs in this field
Explanation: i did the test
