Which of the following relation is a function? A.{(0,2),(3,6),(0,1),(6,3)}B. {(1,2),(6,7),(9,9),(3,7)} C.{(4,5),(1,3),(5,5),(4,0
valkas [14]
Heya user☺☺
Option c is correct
Hope this will help☺☺
9: the answer is 4 to 13
10: the answer is 6 to 13
Answer: im having the same problem
Step-by-step explanation:
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Answer: 37,39,41,43
Answer:
it's the bottom left one
Step-by-step explanation:
Im just a kid, don't ask
So -1/4x+1/2 x would be 1/4 x because -0.25+0.5=0.25
translating 2/3 into 4/6, so we do 4/6-2/6 which would be 1/2.
:) Im an idiot lol
