Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=

so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=

x=

x=

x=

x=

there are no real numbers that satisfy this
504+640=1144 hope this helps!
Expression: 3g+2
cost of 8 games: 3*8=24+2= 26
Hi,
Answer:
k = 
Step-by-step explanation:
Subtract 4k from both sides
6k - 4k = 2k
2k - 8 = 15
Add 8 on both sides (you want to get rid of the 8 in order to leave the k alone)
2k = 23
k = 23/2
Have a good day!
Ok so I did 25 divided by 2 I got 12.5 and 26 divided by 3 and got 8.6 so the best deal would be 8.6 for part A .