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3 years ago

How many hours α day are you on tiktok??

Mathematics

2 answers:

GenaCL600 [577]3 years ago

8 0

All day everyday sadly://

Lesechka [4]3 years ago

6 0

Answer:

24hrs I watch it all day lobg

You might be interested in

Please help I will mark brainlyest

IgorLugansk [536]

Answer:

C. x^5/2 + 6x^3/2 + 1.

Step-by-step explanation:

(x^3 + 6x^2 + x^1/2) / x^1/2

= x^(3 - 1/2) + 6 x(2-1/2) + 1

= x^5/2 + 6x^3/2 + 1.

3 0

3 years ago

Find the solution to the system of equations. You can use the interactive graph below to find the solution. { y = x − 4 y = 4 x

kumpel [21]

ANSWER

$x=-2,y=-6$

EXPLANATION

First equation:

$y = x - 4$

Second equation:

$y = 4x + 2$

Let us equate the two equations and solve for x.

This implies that;

$4x + 2 = x - 4$

Group similar terms to obtain:

$4x - x = - 4 - 2$

Simplify:

$3x = - 6$

Divide both sides by 3

$x = - 2$

Put x=-2 into any of the equations.

I will put x=-2 into the first equation:

$y = - 2 - 4$

This implies that,

$y = - 6$

7 0

3 years ago

Read 2 more answers

Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.

Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0

4 years ago

Suppose that f(x) is the (continuous) probability density function for heights of American men, in inches, and suppose that f(69

anastassius [24]

Answer:

(a) 7.6%

(b) 46.2% 42.4%

Step-by-step explanation:

(a)According to the definition of Continuous probability distribution

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x + h) - F(x - h)}{(x + h) - (x - h)}$

$f(69) = \frac{F(69 + 0.2) - F(69 - 0.2)}{0.4}$

⇒ 0.19 × 0.4 = F(69.2) - F(68.8)

⇒ F(69.2) - F(68.8) = 0.076

⇒ 7.6%

(b) Given F(69) = 0.5

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.2)}{0.2}$

⇒ 0.19 × 0.2 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.038 = 0.462

⇒ 46.2%

$f(x) = \frac{d}{dx}F(x)$

$f(x) = \frac{F(x) - F(x - h)}{x - (x - h)}$

$f(69) = \frac{F(69) - F(69 - 0.4)}{0.4}$

⇒ 0.19 × 0.4 = F(69) - F(68.8)

⇒ F(68.8) = 0.5 - 0.076 = 0.424

⇒ 42.4%

5 0

3 years ago

Is (p3)4 • p8 = p20 true or false ?

Oduvanchick [21]

P3(4) = p12 them p12 * p8 = P160 (false)

8 0

3 years ago