Answer:
122 Degrees
Step-by-step explanation:
Since we are given that angle 1 and 2 make a linear pair:
angle 1 + angle 2 = 180 degrees ----------------------------(1)
We have also been told that angle 2 is 6 more than twice the measure of angle 1
Which means: angle 2 = (2*angle1) + 6 -------------------(2)
From putting the value of angle 2 in (1) from (2)
<em>angle 1 + 2*angle 1 + 6 = 180</em>
<em>3*angle 1 = 174</em>
angle 1 = 58 degrees -----------------------(3)
From (1) and (3):
<em>angle 2 + 58 = 180</em>
angle 2 = 122 degrees
Therefore, the measure of angle 2 is 122 degrees
Answer:
There's no table but
Step-by-step explanation:
4 tickets = $32
8 tickets = $64
Sorry if I didn't help:/.
The total cost of the cord is $4.75
The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
<h3>How to determine the zeros of the function?</h3>
The function is given as:
f(x) = x^3 + 3x^2 + 2x
Factor out x in the above function
f(x) = x(x^2 + 3x + 2)
Set the function to 0
x(x^2 + 3x + 2) = 0
Factorize the expression in the bracket
x(x + 1)(x + 2) = 0
Split the expression
x = 0, x + 1 = 0 and x + 2 = 0
Solve for x
x = 0, x = -1 and x = -2
Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
Read more about zeros of function at
brainly.com/question/20896994
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