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2 years ago

1 pizza costs $0.50 to make. They sell it for $12. Find the percent markup.

Mathematics

1 answer:

Damm [24]2 years ago

3 0

Answer:

ok let me try this again

To explain a markup, let's use an example: Let's say you purchase a box of paper that costs one dollar. You aim for a profit of 50%. By multiplying the cost by 50%, you get $0.50. This is your markup price. Add that to the price that you paid to purchase the box of paper, and now the total is $1.50. This is the selling price of the box of paper. Therefore, your markup percentage is 50%.

did that help i was not a faker though i was just trying to explain it to him/she better and can i have brainlist please

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Assoli18 [71]

-5 + 12 is 7

-2 - 8 is -10

6 0

2 years ago

Which equations may be used to determine the 3 consecutive integers whose sum is 127?

s344n2d4d5 [400]

Answer:

a and b.

Step-by-step explanation:

I’ll explain by giving an example.

Let’s say that: a=3;b=4;c=5; => they all are consecutive -> their sum is 12.

=> if we use a) n=3 => 3*n+3=3*3+3=12 => correct.

b) n+(n+1)+(n+2)= 3+4+5=12=> correct.

c)n+2n+3n=3+6+9=18=>incorrect.

d)3n=3*3=9=>incorrect.

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2 years ago

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0

3 years ago

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Nesterboy [21]

Answer: x^9+3x^8+7x^7

Step-by-step explanation:

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2 years ago

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lubasha [3.4K]

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2). There is no way to win 37 games if you've
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3 years ago