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3 years ago

Hi! can i get some help? Ramadan Mubarak

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

Mode

Step-by-step explanation:

I believe it is mode because mode is the number which appears most in a group of numbers. In the survey he wants to see the most popular, in other words the highest number of votes on a sandwich. Hope this helped. Ramadan Mubarak to you too, im doing this while fasting.

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1. take away five from twelve times f. 2. one-half of the sum of k and six 3.x squared minus the sum of 5 4.the sum of the produ

77julia77 [94]

The expressions formed are,

12f -5
(k+6)/2
x²-x+5
ab+3c
24xy+g

Formation of expressions in 1, 2 and 3:

In 1, twelve times f is, 12f

Taking away 5, it becomes (12f-5)

In 2, sum of k and 6 is, (k+6)

One-half of the above quantity is, (k+6)/2

In 3, sum of 5 with x is, (x+5)

Now, x squared minus the above expression indicates (x²-x+5)

Formation of expressions in 4 and 5:

In 4, product of a and b, is ab and 3 times c is 3c

Sum of the expressions evaluated in the previous statement = ab+3c

In 5, 24 times the product of x and y is, 24xy

Adding, g in the above computed expression, we get, 24xy+g

Learn more about expressions here:

brainly.com/question/17167810

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1 year ago

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Who is Wharton. I don’t get it is it a convo

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3 years ago

Sarah used 2.5 cups of cheese in a dish that serves 5 people. How many cups of cheese is needed

Alekssandra [29.7K]

Answer:

0.5 cups or 1/2 a cup per person

Step-by-step explanation:

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2 years ago

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Answer: B

Step-by-step explanation: Hope this help :D

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2 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

sattari [20]

Answer:

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) 0.09

Step-by-step explanation:

We are given the following in the question:

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)$

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) rate of increase after one day.

We put t = 1

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09$

The rate of increase after 1 day is 0.09

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2 years ago