$\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}$

Second expression:

3 0

1 year ago

Which choice is the most efficient first step to solve this set of

Lisa [10]

Answer:

b) Substitute (3x - 5) for y in the second equation.

Step-by-step explanation:

If using the substitution method, then the second choice is the most efficient first step.

<u>What is the substitution method?</u>

The substitution method can be used to solve a system of equations. It is when you isolate any of the variables from one of the equations and then substitute that value into the other equation.

Here, the first equation already has an isolated variable, y. We can then substitute its value into the second equation. Like so:

⇒ 2x + 6y = 20

⇒ 2x + 6(3x - 5) = 20

Learn more about the substitution method here:

brainly.com/question/27728118
brainly.com/question/26094713

4 0

2 years ago