2 years ago

Find the value of X so that the figures have the same perimeter.

Mathematics

2 answers:

DerKrebs [107]2 years ago

8 0

Can I see the figures?

Anuta_ua [19.1K]2 years ago

4 0

Answer:

i need an image to answer this question

Step-by-step explanation:

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12 = 3 x *blank* × *blank*

mario62 [17]

1.(first blank) 2
2.(second blank) also 2
So 2 and 2
EXPLANATION:
3 x 2 is 6.
6 x 2 is 12.
Boom Im magical

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2 years ago

60 in 63 in What is the length of the hypotenuse? inches Submit

saveliy_v [14]

Answer:

assuming 60 and 63 are the side lengths

87 in is the hypotenuse

Step-by-step explanation:

60^2 + 63^2 = x^2

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2 years ago

IMPORTANT [how do you]Find sin theta if tan theta = 3/4

zvonat [6]

$\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{4}}\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+4^2}\implies c=5
\\\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{hypotenuse}{5}}$

bear in mind that, though the square has two valid roots, one negative and one positive, the hypotenuse is just a radius distance, and therefore is never negative.

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3 years ago

What is the closest side lenght of this square? Area=99 square units

Alex Ar [27]

Answer:

3 $\sqrt{11}$