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Paraphin [41]
3 years ago
13

Find the equation of a line whose slope is 2/5 and y- intercept is 2.write your answer in the form

Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer:

y = 2/5*x + 2 = 0.4x + 2

2/5*x - y + 2 = 0

1) 2*x - 5*y + 10 = 0

2/5*x - y = -2

-1/5*x + 1/2*y = 1

2) x/(-5) + y/2 = 1

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3 years ago
F(x)
Ludmilka [50]
F(x) = 5 + 2x  where x is the number of times he walks the neighbours dog
y-intercept is at y=5 and slope = 2

g(x) :-  As x increases by 4 g(x) decreases by -8  so the slope is -8/4 =  -2
when x = 0, g(x)  = the y intercept  is at -1 + (-8/2) = - 5
so equation of g(x) is  g(x) = -5 -2x
h(x):-    the slope is  (3 - 5) / (1 - 0)      [  difference in y values / diff in x values]
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so we have h(x) = -2x + c   where c = the y-intercept
when x = 0  h(x) = 5
so  c = 5
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  Now j(x)= 2x - 5   - slope is 2 and y intercept = -5
8 0
3 years ago
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4 0
3 years ago
Identify the equation of the circle that has its center at (-16,30) and passes through the origin
dangina [55]

Answer:

(x+16)²+(y-30)²=1156

Step-by-step explanation:

We have given:

center at (-16,30). It means h = -16 and k=30

and it passes through the origin (0,0)

Thus the  radius will be distance between (-16,30) and (0,0)

r=√(-16 - 0)²+(30-0)²

r=√256+900

r²=(√1156)²

r²=1156

Now apply standard equation of circle:

(x-h)²+(y-k)² = r²

(x+16)²+(y-30)²=1156

Thus the equation is (x+16)²+(y-30)²=1156 ....

3 0
3 years ago
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