The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
see below
Step-by-step explanation:
We can use point slope form
y - y1 = m(x-x1)
where m is the slope and ( x1,y1) is a point on the line
y-12 = 3(x-12)
If we want it in slope intercept form
Distribute
y-12 = 3x-36
Add 12 to each side
y-12+12 = 3x-36+12
y = 3x-24
Answer:
48 Yards long
Step-by-step explanation: You multiply 24x 2
Where where is the formula you didn't even post a picture?
