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Illusion [34]
2 years ago
7

Looking for help with number 7! Thank you :)

Mathematics
1 answer:
san4es73 [151]2 years ago
7 0
I think the best anwser is u can try b
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Need help asap please!!<br> This is the only one i don’t know i’m stuck!
lyudmila [28]

Answer:

Reminder that is this form  a(b)^x  where  a > 0

When   b > 0  but < 1 that is a decay function

When   b > 1 than its a growth function

Step-by-step explanation:

So following this you can figure out the answer

g(x)=0.3(x)      

this is neither since there is no exponent (linear)

H=72(56)^t    

this is growth since b  = 56

A=(43)^t        

this is growth since b  = 43 ("a" is understood as "1")

H=5.9(0.82)^t      

this is decay since b =  0.82

y=0.8(3.6)^t      

this is growth since b = 3.6

f(t)=0.72(15)^t    

this is growth since b  = 14  

A=49(8)^t      

this is growth since b  = 8

6 0
2 years ago
An architectural drawing lists the scale as 1/4 = 1. If a bedroom measures 3 1/2 by 5 1/4 on the drawing, how large is the bedro
mars1129 [50]
The bedroom is 14x21. I hope this helps :)
3 0
3 years ago
Read 2 more answers
He lays the shorter edfe<br> and finds the frame
il63 [147K]
By laying on the short edge the frame of it is 6
5 0
2 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
gulaghasi [49]

Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

P(A|B)=\frac{1}{3}

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

4 0
3 years ago
Read 2 more answers
2(x - 1) – 7x = 18 – 5(x + 4)
iragen [17]
I hope this will help

4 0
3 years ago
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