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Gemiola [76]
3 years ago
13

F(x)=2x+1 and g(x)=x^2-7, find (f g) (x)

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

The answer is (f o g)(x) = 2x^2 - 13

In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).

f(x) = 2x + 1 ----> Remove variable.

f(x) = 2(      ) + 1 ----> Insert g(x)

(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute

(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify

(f o g)(x) = 2x^2 - 13

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Answer:

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Step-by-step explanation:

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vitfil [10]
<h3>Answer: 6pi radians</h3>

(this is equivalent to 1080 degrees)

======================================

Explanation:

f(x) = sin(x/3)

is the same as

f(x) = 1*sin( (1/3)(x-0) )+0

and that is in the form

f(x) = A*sin( B(x-C) )+D

The letters A,B,C,D are explained below

A = helps find the amplitude

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C = determines phase shift (aka left/right shifting)

D = determines vertical shift = midline

All we care about is the value of B as that is the only thing that is connected to the period T

--------

Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,

B = 2pi/T

1/3 = 2pi/T

1*T = 3*2pi ... cross multiply

T = 6pi

The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).

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