Solution: $50
Step by step: you can set up the equation that 120%x=60, but for it to be easier you can just change 120% to 1.2 (one whole and 2 tenths or 120) to get the equation 1.2x=60, then to find x just do the algebra
1.2x=60
x=60/1.2
x=50
Answer: 29 feet (deepest) at 6 am
21 feet (shallowest) at Midnight & Noon
<u>Step-by-step explanation:</u>
y = -4 cos (π/6)t +25
Amplitude (A) = 4
-A means it is a reflection over the x-axis (starts at minimum)<em> </em>
Period = 2π/B → Period = 12
Phase shift = C/B → Phase Shift = 0
Midline (D) = 25
Midline (D) ± Amplitude (A) = Max & Min
Max: 25 + 4 = 29
Min: 25 - 4 = 21
Change the coordinates of y = cos (x) as follows:
- x-value: Add C then divide by B
- y-value: Multiply by A then add D
Note that the equation shows: A = -4, B = π/6, C = 0, D = 25
Rick has 1 1/3, or 4/3, pounds of sugar.
He needs to pour 1/4 of this amount into the bowl.
4/3 * 1/4 Multiply the numerators and the denominators
(4*1) / (3*4) = 4/12 Simplify, 4/12 can be simplified to 1/3.
He poured 1/3 pound of sugar.
Now, for flour, we need to find 1/4 of 2/3, using the same process:
(2/3) * (1/4) = (2*1) / (3*4) = 2/12 = 1/6
He poured 1/6 pound of flour
Answer:
Rate of change or slope = 
Step-by-step explanation:
It is common that most lines that are graphed are in slope intercept form.
y=mx+b
M represents the slope.
In the question you're asking M = 1/3
Answer: a. 0.05
b. 0.40
c. 0.85
Step-by-step explanation:
Let F= Event that a certain motorist must stop at the first signal.
S = Event that a certain motorist must stop at the second signal.
As per given,
P(F) = 0.45 , P(S) = 0.5 and P(F or S) = 0.9
a. Using general probability formula:
P(F and S) =P(F) + P(S)- P(F or S)
= 0.45+0.5-0.9
= 0.05
∴ the probability that he must stop at both signals = 0.05
b. Required probability = P(F but (not s)) = P(F) - P(F and S)
= 0.45-0.05= 0.40
∴ the probability that he must stop at the first signal but not at the second one =0.40
c. Required probability = P(exactly one)= P(F or S) - P(F and S)
= 0.9-0.05
= 0.85
∴ the probability that he must stop at exactly one signal = 0.85
