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marishachu [46]
3 years ago
9

An army of orcs has marched upon King Amit's stronghold, setting up camp a safe distance away (or so they think!). What the orcs

don’t know is that the king and his engineers have spent the past decade developing advanced catapulting technology. King Amit has created a map to help him compute the distance from each of his two best catapults to the enemy orc camp (shown below). To what distance should King Amit calibrate catapult B to fire?

Mathematics
2 answers:
sveta [45]3 years ago
8 0

The interior angles of any triangle add up to 180º in measure, which means the missing angle has measure

180º - 96º - 58º = 26º

By the law of sines, we have

(145 m)/sin(26º) = ?/sin(96º)

==>  ? = sin(96º)/sin(26º) (145 m) = 328.96 m

dybincka [34]3 years ago
8 0

Answer: the answer is 328.96

Step-by-step explanation:

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Zara filled up her car with 15 gallons of gas. If Zara paid $33.00, what was the price per gallon of gas?
djyliett [7]

Answer:

$2.20 per gallon.

Step-by-step explanation:

That is 33/15 = $2.20 per gallon.

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Answer:

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Step-by-step explanation:

So I think it's the first one, the fourth one, and the last one, and the second one.

I hope it helps you!

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3 years ago
What’s the best answer
Marizza181 [45]
A is your best answer

5 0
4 years ago
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a falling object travels a distance given by the formula d=5t + 16t^2 ft, where t is measured in seconds. how long will it take
Butoxors [25]

Its given that

d=5t+16t^{2}

We need to find t when d = 74

Therefore, 74=5t+16t^{2} or

16t^{2}+5t-74 = 0

16t^{2}+37t-32t-74 = 0

t(16t + 37) - 2(16t + 37) = 0

(t - 2)(16t + 37) = 0

t - 2 = 0 or 16t + 37 = 0

t couldn't be negative.

Therefore, t = 2

Hence, it will take 2 seconds for the object to travel 74 feet.










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3 years ago
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To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne
Naily [24]

Answer:

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

\hat p=\frac{67}{150}=0.447 estimated proportion of applicants who request financial aid

p_o=0.35 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0
3 years ago
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