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Andrews [41]
3 years ago
5

Graph x > -5 on a number line.

Mathematics
1 answer:
Natasha2012 [34]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

that is correct unless your asking something else?

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Jack bought 8 tokens for $4.40 at this rate how many tokens can she buy with $6.05
Ipatiy [6.2K]

Answer:

11

Step-by-step explanation:

First, find how much a token costs.

4.40 ÷ 8 = .55

Then divide 6.05 by .55 to get 11.

3 0
2 years ago
Ritz can eat 8 apples in 15 minutes. How long does it take Ritz to eat 16 apples at the same rate?
natka813 [3]
The rate Ritz can eat apples is 8/15 apples per minute.

Set the rate (which is measured apples / minutes) equal to 16 apples / t minutes.

(8/15) = (16/t)

Cross multiply.

16*15 = 8t

t = 20

The answer is 30 minutes. You could solve the problem with basic reasoning as well. 16 is twice the number of apples as 8, so the time it takes to eat them will be double 15 minutes.
5 0
3 years ago
How many different ways can the line above be named? What are those names?
suter [353]
Its either 3 or 2 
the third way matches only if there's another reference  line 
I'll go with 3


7 0
3 years ago
Read 2 more answers
Kelly purchased 5 containers of ice cream for a party. Each container holds 8 cups of ice cream. Before the party, her brother a
victus00 [196]

Given:

Kelly purchased 5 containers of ice cream for a party.

Each container holds 8 cups of ice cream.

Her brother ate 2 cups of ice cream.

One serving of ice cream = 2/3 of a cup.

To find:

Number of servings of ice cream will be left for the party?

Solution:

We have,

1 container = 8 cups of ice cream

5 containers = 5×8 = 40 cups of ice cream

Her brother ate 2 cups of ice cream. So, remaining cups of ice cream is

40-2=38 cups

Now,

\dfrac{2}{3} of a cup = 1 serving

1 cup = \dfrac{3}{2} serving

38 cup = 38\times \dfrac{3}{2} serving

            = 19\times 3 serving

            = 57 serving

Therefore, 57 servings of ice cream will be left for the party.

4 0
2 years ago
Question 5: How long will it take for 2 g of a sample of iodine-131, which has a half-life of about 8 days, to decay to 0.04 g?
Aleonysh [2.5K]

This problem can be represented through the following equation

A = A₀(1/2)^t/h

where

A----------->  is the amount of substance left after time t

A₀ ----------> is the original amount---------> 2 g

h------------->  is the half-life-----------> 8 days

for A=0.04 g

t=?

0.04 = 2(1/2)^t/8

0.02 = (1/2)^t/8

Take ln on both sides:

ln(0.02) = ln [(1/2)^t/8]

ln(0.02) = (t/8)(ln 1/2)

t = 8*ln(0.02)/ln(1/2)

t = 45.15 days

the answer is 45.15 days

4 0
2 years ago
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