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son4ous [18]
3 years ago
14

You know that there is a strong correlation between the consumption of ice cream and body weight. The Pearson's r = 0.78. You al

so know that the average consumption of ice cream per week is five grams with a standard deviation of 1.5 grams. The average weight is 65 kg with a standard deviation of 15 kg. What is the formula of the regression line?
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

ŷ = 26 + 7.8x

ŷ = 7.8 + 26x

ŷ = -502 + 0.078x

ŷ = 0.078 - 502x

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VladimirAG [237]
Answer: z= -5

Step by Step:
-4(2z+6)-12=4
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3 years ago
5/4+5/4=_ × 1/4 plz help me​
Tanya [424]

Answer:

10/4

Step-by-step explanation:

4 0
3 years ago
Find area of the circle. Thanks so much
hammer [34]

Answer:

176.63 in²

Step-by-step explanation:

Area = πr²

Area = 3.14 * (7.5²)

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If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0
3 years ago
Read 2 more answers
Let F=(2x,2y,2x+2z)F=(2x,2y,2x+2z). Use Stokes' theorem to evaluate the integral of FF around the curve consisting of the straig
Brilliant_brown [7]

Stokes' theorem equates the line integral of \vec F along the curve to the surface integral of the curl of \vec F over any surface with the given curve as its boundary. The simplest such surface is the triangle with vertices (1,0,1), (0,1,0), and (0,0,1).

Parameterize this triangle (call it T) by

\vec s(u,v)=(1-v)((1-u)(1,0,1)+u(0,1,0))+v(0,0,1)

\vec s(u,v)=((1-u)(1-v),u(1-v),1-u+uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to T to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=(0,1-v,1-v)

Divide this vector by its norm to get the unit normal vector. Note that this assumes a "positive" orientation, so that the boundary of T is traversed in the counterclockwise direction when viewed from above.

Compute the curl of \vec F:

\vec F=(2x,2y,2x+2z)\implies\mathrm{curl}\vec F=(0,-2,0)

Then by Stokes' theorem,

\displaystyle\int_{\partial T}\vec F\cdot\mathrm d\vec r=\iint_T\mathrm{curl}\vec F\cdot\mathrm d\vec S

where

\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\,\mathrm dS

\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\mathrm d\vec S=\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv

The integral thus reduces to

\displaystyle\int_0^1\int_0^1(0,-2,0)\cdot(0,1-v,1-v)\,\mathrm du\,\mathrm dv=\int_0^12(v-1)\,\mathrm dv=\boxed{-1}

3 0
3 years ago
Mr. Rowley has 16 homework papers and 14 exit tickets to return. Ms. Rivera has 64 homework papers and 60 exit tickets they have
yarga [219]
16:64 (Rowley to Rivera homework ratio)
14:60 (Rowley to Rivera exit ratio)

The ratios aren't equivalent because when they are simplified, the first ratio is 1:4, and the second is 7:30, thus meaning they aren't equal.


4 0
4 years ago
Read 2 more answers
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