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aleksandrvk [35]
3 years ago
10

Evaluate: log279 I just need the answer

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

2.44560420

Step-by-step explanation:

xxMikexx [17]3 years ago
6 0
The answer to Log279 is about 2.445
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What would x be in this parallelogram ?
irina [24]

Answer:

18

Step-by-step explanation:

The diagonals of a parallelogram <em>bisect</em> each other, which is to say they split each other in half, and since each half length is equal to the other, we can say that

3x + 3 = 6x - 57

Which, after some algebraic manipulation, gives us the solution

x = 18.

8 0
3 years ago
Multiply and simplify. (3x+5)(2x2−3x+2) Enter your answer, in standard form, in the box.
Sveta_85 [38]

Answer:

6x^3+x^2-9x+10

Step-by-step explanation:

We have the product, (3x+5)(2x^{2}-3x+2).

On simplifying the product, we get,

(3x+5)(2x^{2}-3x+2)

i.e. 6x^3-9x^2+6x+10x^2-15x+10

i.e. 6x^3+x^2-9x+10

Thus, the standard form of the product (3x+5)(2x^{2}-3x+2) is 6x^3+x^2-9x+10.

7 0
3 years ago
Read 2 more answers
Calculus- need help with this problem. Above the sigma is an infinity sign and below it says n=1
WITCHER [35]

Answer: B

Step-by-step explanation:

S = An/1 - r

A1 = 6

6/1 - (-1/4)

6/1 + (1/4)

6/1.25

S = 4.8 or 24/5

5 0
4 years ago
Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
3 years ago
5. Alani paid $8.50 to get in the movies. Before she left home her parents
solniwko [45]

Answer:

3 peices

Step-by-step explanation:

6 0
3 years ago
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