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Dominik [7]
3 years ago
6

What is (2/9) - (1/3 + 5/9)

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0
Step 1; Write Out the Problem
(2/9) - (1/3 + 5/9) = ?
Step 2; Perenthesis First/Make the Dinominator the Same
(2/9) - (3/9 + 5/9) = ?
Step 3; Add
(2/9) - (8/9) = ?
Step 4; Take Out the Perenthesis
2/9 - 8/9 = ?
Step 5; Subtract
2/9 - 8/9 = 6/9
Step 6; Write Out the Whole Answer
(2/9) - (1/3 + 5/9) = 6/9
Nice
ad-work [718]3 years ago
3 0
(2/9) - (3/9 + 5/9)
2/9 - 8/9
-6/9.
Simplified, it is - 2/3. Hope it helps! :)
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The length of an inflatable swimming poll is 2 meters 12 centimeters. How long is the pool in millimeters?
yKpoI14uk [10]

Answer:

2120 mm

Step-by-step explanation:

→ Convert 2.12 metres into centimetres

2.12 × 100 = 212 cm

→ Multiply by 10 to get into mm

212 × 10 = 2120 mm

7 0
2 years ago
Solve these problems and show your work! ONLY HAND WRITTEN answers will be accepted! When
Dahasolnce [82]

For Kohl’s:

Purchase Price:

$60

Discount:

(60 x 25)/100 = $15.00

Final Price:

60 - 15.00 = $45.00

You would save $15.00 from Kohl’s and pay only $45.00

For Target:

Purchase Price:

$38

Discount:

(38 x 15)/100 = $5.70

Final Price:

38 - 5.70 = $32.30

You would save $5.70 from Target and pay only $32.30

Hope this helps! :)

3 0
4 years ago
What is the value of the expression?
Elza [17]
-(5 + (-11.3)) + (-4.3)

-(5 - 11.3) + (-4.3)

Distribute -1 into the parenthesis:

-5 + 11.3 + (-4.3)

-5 + 11.3 - 4.3

Add:

6.3 - 4.3

Subtract:

2
8 0
4 years ago
At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
Which expression is equivalent to 12^4(x-3)(x+5)/30x(x+3)(x+5)
Rainbow [258]

Answer:

x+5

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
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