What is the area of AABC? Round to the nearest tenth of a square unit.

Blababa [14]

Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 30/5 = 6.Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 30/-3 = -10.Slope is -5/-3 = 1.66666666666667. Equation in slope-intercept form: y=1.66666666666667*x+-10.

6 0

3 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can use as an estimator for p $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

3 0

3 years ago

Scientific notation of 0.00000008

RSB [31]

8*10^-8 is the answer

6 0

3 years ago

A person borrowef Rs 16000 from a bank at 12.5% pet annum simple intrest and lent the whole amount to shopkeeper at the sam rate

r-ruslan [8.4K]

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 = (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

8 0

3 years ago

PLEASEE 7TH GRADE MATH

Andrews [41]

Answer:

so first question is b)8/5p=c, explanation in comments and your second question is 25%explanation in comments!! Have a good day and hope this helped!!

Step-by-step explanation:

7 0

3 years ago