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Andrews [41]
4 years ago
5

Which expression is equivalent to

Mathematics
2 answers:
ozzi4 years ago
5 0
The answer for the question shown above is the first option: x^2(x^2)^1/4
 When you simplify the expression, you obtain the equivalent expression:

 (x^10)^1/4
 [(x^8)(x2)]^1/4
 x^2(x^2)^1/4

 Therefore, the asnwer is the option mentioned before.
laila [671]4 years ago
5 0
Answer: the first option:

x^2 (\sqrt[4]{x^2} )

Explanation:

1) Since the exponent of the radicand (the letter inside the root) is less than the index of the radical you can extract partially the letter from the radical.

2) You divide the exponent (10) by the index of the radical (4) and that gives a quotient of 2 and a remainder of 2.

3) The quotient means that the letter appears out of the radicand with that exponent. That is x².

4) The remainder gives the exponent of the letter that stands inside the root.  That is x².

Therefore, the result is that x² leaves the root and x² stands inside the root.

You can also do it in this way:

\sqrt[4]{x^{10}} = \sqrt[4]{x^8x^2} =  \sqrt[4]{x^8}  \sqrt[4]{x^2} = x^{2}  \sqrt[4]{x^2}
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Suppose that the weights of passengers on a flight to Greenland on Frigid Aire Lines are normal with mean 175 pounds and standar
Natali5045456 [20]

Answer:

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 175, \sigma = 22

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?

90th percentile

The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 175}{22}

X - 175 = 22*1.28

X = 203.16

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

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Step-by-step explanation:

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