Answer:
y =
x - 
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 4x + 38 is in this form with slope m = - 4
The line ST is perpendicular to line RS ( angles in a square are 90° )
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= 
y =
x + c ← is the partial equation
To find c substitute (2, - 4) into the partial equation
- 4 =
+ c ⇒ c = - 4 -
= - 
y =
x -
← equation of ST
Answer:
$110.37
Step-by-step explanation:
Assuming the monthly payment is made at the beginning of the month, the formula for the monthly payment P that gives future value A will be ...
... A = P(1+r/12)((1+r/12)^(nt) -1)/(r/12) . . . . n=compoundings/year, t=years
... 14000 = P(1+.11/12)((1+.11/12)^(12·7) -1)/(.11/12)
... 14000 = P(12.11)((1+.11/12)^84 -1)/0.11 ≈ P·126.84714 . . . . fill in the given values
... P = 14000/126.84714 = 110.37 . . . . . divide by the coefficient of P
They should deposit $110.37 at the beginning of each month.
Answer:
C)infinitely many solutions
Step-by-step explanation:

Answer:
3x = 2(-3x + 1)
Step-by-step explanation:
I think that's it I think it could be wrong but I tried
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....