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DENIUS [597]
3 years ago
12

W−2+2w=6+5w please helppp

Mathematics
2 answers:
Lerok [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Simplifying

W + -2 + 2w = 6 + 5w

Reorder the terms:

-2 + W + 2w = 6 + 5w

Solving

-2 + W + 2w = 6 + 5w

Solving for variable 'W'.

Move all terms containing W to the left, all other terms to the right.

Add '2' to each side of the equation.

-2 + W + 2 + 2w = 6 + 2 + 5w

Reorder the terms:

-2 + 2 + W + 2w = 6 + 2 + 5w

Combine like terms: -2 + 2 = 0

0 + W + 2w = 6 + 2 + 5w

W + 2w = 6 + 2 + 5w

Combine like terms: 6 + 2 = 8

W + 2w = 8 + 5w

Add '-2w' to each side of the equation.

W + 2w + -2w = 8 + 5w + -2w

Combine like terms: 2w + -2w = 0

W + 0 = 8 + 5w + -2w

W = 8 + 5w + -2w

Combine like terms: 5w + -2w = 3w

W = 8 + 3w

Simplifying

W = 8 + 3w

Allisa [31]3 years ago
5 0
W=-4
start by subtracting 2w from both sides
then subtract the single w on the left, getting -2=6+2w
next, subtract the 6 from both sides and you get -8=2w
then, just decide both sides by 2 and you get -4=w
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Step-by-step explanation:

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2. Expand by distributing terms.

{6x}^{3}  +  {15x}^{2}  - 3x - 3( {2x}^{2}  + 5x - 1)

3.Expand by distributing terms.

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4. Remove parentheses.

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5. Collect like terms.

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6. Simplify.

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{6x}^{3}  +  {9x}^{2}  - 18x + 3

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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

For this case we can use as estimator for the proportion \hat p =0.5, since we don't have any other previous info. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

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