Ask question

Ask question

All categories

3 years ago

12

(-4, 2) and (3, -3)?

1 answer:

Gnom [1K]3 years ago

6 0

Answer:

$m=-\frac{5}{7}$ ; see graph.

Step-by-step explanation:

Using the slope formula:

$m=\frac{rise}{run}=\frac{-3-2}{3+4}=\frac{-5}{7}=-\frac{5}{7}$

You might be interested in

100 points, put nonsense, get reported. Susan wants to build a floor to put at the bottom of her tree house. She made the scale

Elanso [62]

Divide the length of the scale drawing by the scale (2.5) then multiply that by the scale feet (3)

11 inches / 2.5 = 4.4

4.4 x 3 = 13.2 feet

Answer: 13.2 feet

3 0

2 years ago

Read 2 more answers

Question 3 of 10

iragen [17]

Answer:

Question 3 of 10 The answer should be 7

Step-by-step explanation:

The reason is because if it is out of 100 7/100 is still 7%

6 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

<u>case b)</u> $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

<u>case c)</u> $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

<u>case d)</u> $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

Identify the rule for each pattern.

Angelina_Jolie [31]

Answer:

ar some point pattern A will have the same numbers as pattern B as it moves along like if you add 3 for 2 more times in pattern A it will have 24 and so on..

3 0

3 years ago

Select the correct answer.

My name is Ann [436]

Answer:

B

Step-by-step explanation:

That was actually trickier than I thought it would be

I was looking for 4(x-4), but 4(x-2)(x+2) also works

7 0

3 years ago

Read 2 more answers