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dezoksy [38]
4 years ago
14

identify and equation in point-slope form for the line perpendicular to y=-1/2x-7 that passes through (-3,-2)

Mathematics
1 answer:
bazaltina [42]4 years ago
8 0

Answer:

  y +2 = 2(x +3)

Step-by-step explanation:

The equation in point-slope form for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

The slope of your given line is the coefficient of x, -1/2. The slope of a perpendicular line will be the negative reciprocal of that: -1/(-1/2) = 2. So, you have m = 2, (h, k) = (-3, -2), and your desired equation is ...

  y -(-2) = 2(x -(-3)) . . . . . . which can be simplified to ...

  y +2 = 2(x +3)

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6x+Q=Px+15 what values of P and Q result in an equation with exactly one solution?
NNADVOKAT [17]

P = 6

Q = 15

How to solve:

Note the equal sign. This means that both expression's out come must equal each other. For that to happen, everything inside both expressions must equal each other. In this case:

6x + Q = Px + 15; 6x + 15 = 6x + 15

hope this helps

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4 years ago
The public library has volunteers shelve books after they have been returned. When Lisa arrives to volunteer, there are 5 non-fi
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Answer:

65 non-fiction books need to be shelved

Step-by-step explanation:

This question can be solved using a rule of three.

For each 5 non-fiction books, there are 9 fiction books. How many non-fiction books are there when there are 117 fiction books?

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4 years ago
What is the probability of rolling at least one six in three rolls of die
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Step-by-step explanation:

4 0
3 years ago
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8 0
3 years ago
Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ
erma4kov [3.2K]

Answer:

a

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b

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c

  Since the integral has an infinite interval of integration, it is a Type 1 improper integral

d

     Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering  a

          \int\limits^4_3 {\frac{x}{x- 3} } \, dx

Looking at this we that at x = 3   this  integral will be  infinitely discontinuous

Considering  b    

        \int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx

Looking at this integral we see that the interval is between 0 \ and  \  \infty which means that the integral has an infinite interval of integration , hence it is  a Type 1 improper integral

Considering  c

       \int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx

Looking at this integral we see that the interval is between -\infty \ and  \  \infty which means that the integral has an infinite interval of integration , hence it is  a Type 1 improper integral

Considering  d

        \int\limits^{\frac{\pi}{4} }_0  {cot (x)} \, dx

Looking at the integral  we see that  at  x =  0  cot (0) will be infinity  hence the  integral has an infinite discontinuity , so  it is a  Type 2 improper integral

     

7 0
3 years ago
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