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dezoksy [38]
3 years ago
14

identify and equation in point-slope form for the line perpendicular to y=-1/2x-7 that passes through (-3,-2)

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0

Answer:

  y +2 = 2(x +3)

Step-by-step explanation:

The equation in point-slope form for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

The slope of your given line is the coefficient of x, -1/2. The slope of a perpendicular line will be the negative reciprocal of that: -1/(-1/2) = 2. So, you have m = 2, (h, k) = (-3, -2), and your desired equation is ...

  y -(-2) = 2(x -(-3)) . . . . . . which can be simplified to ...

  y +2 = 2(x +3)

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Ok, first group x terms
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f(x)=1(x²+4x)-8
take 1/2 of the linear coefient and square it
4/2=2, (2)²=4
add positive and negative of it insides the parenthasees
f(x)=1(x²+4x+4-4)-8
factor perfect square
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distribute
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that is where the x intercept are

and completed square form is
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