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3 years ago

What is the value of x in this equation 1.54x+6.814=8.2

Mathematics

1 answer:

Kruka [31]3 years ago

7 0

Hi the answer is x=9/10

Hope I helped! if somebody could answer my most recent question that would be AMAZING!

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For this spinner, what are the following probabilities? Answer in simplest fraction form using the form: x/y

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2 years ago

Is t-8=3t+1 a solution , no solution or a infinite solution

olasank [31]

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Answer is One solution.

3 0

3 years ago

Can someone help me pls!!

nordsb [41]

Answer:

$a=1$

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite sides of a parallelogram are equal.

Therefore, set any two opposite sides equal to each other to solve for $a$ :

$a+3=2a+2,\\\\3=a+2,\\a=\boxed{1}$

7 0

3 years ago

Read 2 more answers

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

3 years ago