All categories

3 years ago

What is the product? (-2x-9y^2)(-4x-3)

Mathematics

2 answers:

telo118 [61]3 years ago

6 0

Answer:-8x^2-6x+36xy^2+27y^2

Step-by-step explanation:

using the FOIL method

amid [387]3 years ago

5 0

The product of $(-2x-9y^2 )(-4x-3)$ is $8x^2+27y^2+6x+36xy^2$

Explanation:

Given:

$(-2x-9y^2 )(-4x-3)$

Let the above equation is equal to k

$k= (-2x-9y^2 )(-4x-3)$

Now, we will solve the right hand side of the above equation

$k=8x^2+6x+36xy^2+27y^2$

So, the above equation would become

$k=8x^2+27y^2+6x+36xy^2$

So, the final answer of the above product is

$8x^2+27y^2+6x+36xy^2$

You might be interested in

Do not give me any links or files.

Paha777 [63]

Answer:

972 u³

Step-by-step explanation:

The radius is 9 . We can use formula ,

⇒ V = 4/3 π r³

⇒ V = 4/3 × π × 9³

⇒ V = 4 × π × 81 × 3

⇒ V = 972 unit³

7 0

3 years ago

Find all numbers whose absolute value is 5.

melamori03 [73]

Answer:

5 , -5

Step-by-step explanation:

c'mon this is easy. the absolute value of a number is that numbers distance away from zero on the number line. 5 and -5 are the only numbers that are five intergers away from zero.

3 0

2 years ago

Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2

Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: $3x - 2$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: $-9y$

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: $-7x^2 + 4x$

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: $-\frac{1}{2} x^2$

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: $8xy$

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

6 0

2 years ago

Geometry help needed!

salantis [7]

Answer:

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Step-by-step explanation:

midpoint formula $(\frac{x_{1}+x_{2} }{2} ,\frac{y_{1} +y_{2} }{2})$

A(2,4) C(2,-4)

$\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2} =\frac{0}{2} =0$

(2,0)

C(2,-4) B(8,-4)

$\frac{8+2}{2} =\frac{10}{2} =5$

$\frac{-4-4}{2} =\frac{-8}{2} =-4$ midpoint is (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1}) ^{2} }$

$d=\sqrt{(5-2)^{2} +(-4-0)^{2} } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5$

3 0

2 years ago

A cone is 3 inches high and has a base with a surface area of 7 square inches. What is the volume of the cone?

lawyer [7]

Answer: the answer should be 7

Step-by-step explanation: V=πr2h

3=π·1.52·3

3≈7.06858

you can find the radius for the area of the base 7 by dividing by $\pi$ like such 7/3.1459 the squared because remember its in r2 form which give you 1.5 then plug this in for one of two ways to solve A· $\pi$ 1/3 or V=πr2h

4 0

3 years ago