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Mademuasel [1]
3 years ago
8

-5/2 x 5/7 help me i bad at math

Mathematics
1 answer:
saw5 [17]3 years ago
3 0

Answer:

Step-by-step explanation:

assuming that the X is a multiplication symbol and not a variable, because the multiplication symbol is * not x, 5*5/2*7=25/14=1 and 11/14

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Point M is located at (7,1).
Charra [1.4K]

I think it is possibly point b

8 0
2 years ago
The product of 7 and a number is 126. Find the number
fenix001 [56]

Answer:

18

Step-by-step explanation:

Product of 7 and a number is 126.

Let's form the equation,

→ 7 × x = 126

The required value of x will be,

→ 7 × x = 126

→ x = 126/7

→ [ x = 18 ]

Hence, the number is 18.

6 0
2 years ago
The difference between a number and four is multiplied by negative five. The result is twenty. What is the number?
spayn [35]
(n-4)*-5=20           Answer is  n= 8
4 0
3 years ago
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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
Is it a proportional or not proportional
UNO [17]

Answer:

it is

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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