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Hoochie [10]
3 years ago
13

−9x (5x+4 ) +10 (x+3) can someone please solve his for me thank u step by step please i really need to find out how to do it

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

-45x^{2}-26x+30

Step-by-step explanation:

So first you let's divide this equation into three parts.

Part one -9x(5x+4)

  1. Step one: you have to distribute the -9x to the numbers in the parentheses. That would leave us with a -9x*5x = -45x^{2} and -9x*4 = -36x
  2. Step two: Put the answers together. That would leave us with -45x^{2}-36x.

Part two 10(x+3)

  1. Step one: you have to distribute the 10 to the numbers in the parentheses. That would leave us with a 10*x = 10x and 10*3 = 30
  2. Step two: Put the answers together. That would leave us with 10x+30

Part three solve

  1. Step one: combine and put together what you have solved for. That would leave us with a -45x^{2}-36x+ 10x+30
  2. Step two: combine like terms. The like terms here are -36x and 10x. When you combine them you would get -26x.
  3. Step three: Write the equation in standard form. Therefore the answer is -45x^{2}-26x+30.

Let me know if anything is confusing!

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find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
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