Given the function f(x)=x^2 - 2x^5 Determine the instantaneous rate of change at f at x=4.
1 answer:
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4.
seems to be a geometric sequence
common ratio is -4
first erm is -2
5. x=-1
remember x^-1=1/x
f(-1)=4(7^-1)=4(1/7)=4/7
f(2)=4(7^2)=4(49)=196
6. remember
(ab)/(cd)=(a/c)(b/d)
also
(x^m)/(x^n)=x^(m-n)
and
(x^m)(x^n)=x^(m+n)
so
=
(
)(
)=
(0.5)(
=
(0.5)(10^-4)=
(5)(10^-1)(10^-4)=
(5)(10^(-1-4)
5*10^-5
4.
5. f(-1)=4/7
f(2)196
6. 5 times 10^-5
seems to be a geometric sequence
common ratio is -4
first erm is -2
5. x=-1
remember x^-1=1/x
f(-1)=4(7^-1)=4(1/7)=4/7
f(2)=4(7^2)=4(49)=196
6. remember
(ab)/(cd)=(a/c)(b/d)
also
(x^m)/(x^n)=x^(m-n)
and
(x^m)(x^n)=x^(m+n)
so
(
(0.5)(
(0.5)(10^-4)=
(5)(10^-1)(10^-4)=
(5)(10^(-1-4)
5*10^-5
4.
5. f(-1)=4/7
f(2)196
6. 5 times 10^-5