Answer:
a) 0.1587
b) 0.0475
c) 0.7938
Step-by-step explanation:
Let's start defining our random variable.
X : ''Thickness (in mm) of ancient prehistoric Native American pot shards discovered in a Hopi village''
X is modeled as a normal random variable.
X ~ N(μ,σ)
Where μ is the mean and σ is the standard deviation.
To calculate all the probabilities, we are going to normalize the random variable X.
We are going to call to the standard normal distribution ''Z''.
[(X - μ) / σ] ≅ Z
We normalize by subtracting the mean to X and then dividing by standard deviation.
We can find the values of probabilities for Z in a standard normal distribution table.
We are going to call Φ(A) to the normal standard cumulative distribution evaluated in a value ''A''
a)
Φ(-1) = 0.1587
b)
1 - Φ(1.666) = 1 - 0.9525 = 0.0475
c)
Φ(1.666) - Φ(-1) = 0.9525 - 0.1587 = 0.7938
Answer:
-19561285.5554
Step-by-step explanation:
Gonna do a little subbing here...
for 40 pgs of express proof reading....3 bucks per pg...c = 3
40(3) - 0.05(40(3)) = T
120 - 0.05(120) = T.....120 - 6 = T.....114 = T
so express proofreading cost 114
for 40 pgs of basic proof reading....c = 3.95
40(3.95) - 0.05(40(3.95) = T
158 - 0.05(158) = T....158 - 7.9 = T.....150.10
so basic proof reading costs 150.10
for 40 pgs of extended proof reading....c = 5
40(5) - 0.05(40(5) = T
200 - 0.05(200) = T....200 - 10 = 190
so extended proof reading is 190
no need to go further....the extended proof reading is gonna be ur answer...the best quality of editing that keeps it at 190
Answer: 24.2° SouthWest
<u>Step-by-step explanation:</u>
First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>
I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.
<u>Perpendicular (x):</u>
cos 35° = adjacent/hypotenuse
cos 35° = x/160
→ x = 160 cos 35°
<u>Angle (θ):</u>
sin θ = opposite/hypotenuse
sin θ = x/320
sin θ = 160 cos 35°/320
θ = arcsin (160 cos 35°/320)
θ = 24.2°
Direction is down (south) and left (west)
Domain is [-10,∞)
2 is included , only at x=2 new function begins
Range is the values of y , so range is [-7]∪[-4,6
I think, it should be like this.
