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arlik [135]
2 years ago
9

a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how

many of each kind of coin are there?
Mathematics
1 answer:
RideAnS [48]2 years ago
8 0
For this case, the first thing we must do is define variables:
 x: number of nickels
 y: number of dimes
 z: number of quarters
 We now write the system of equations:
 0.05x + 0.10y + 0.25z = 6

x + y + z = 52

y = 2x
 Solving the system of equations we have:
 x = 14

y = 28

z = 10
 Answer:
 
14 nickels
 
28 dimes
 
10 quarters
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The expression can be solved by expanding the bracket and multiplying out the terms

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Step-by-step explanation:

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