Question

a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how many of each kind of coin are there?

Answer 1

For this case, the first thing we must do is define variables:
 x: number of nickels
 y: number of dimes
 z: number of quarters
 We now write the system of equations:
 $0.05x + 0.10y + 0.25z = 6 x + y + z = 52 y = 2x$
 Solving the system of equations we have:
 $x = 14 y = 28 z = 10$
 Answer:
 14 nickels
 28 dimes
 10 quarters