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inn [45]
3 years ago
9

❗️PLEASE HELP ❗️ Bill makes 30 flags in 3 3/4 hours. How many flags can Bill make in 3 hours

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer:

30/ 15 = 2, 2 * 12 = 24 Answer: 24 flags

Step-by-step explanation:

I split it up into 1/4’s. Hope you get at good score.

You might be interested in
2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you
ANEK [815]

Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

7 0
3 years ago
PLEASE HELP ASAP.
alexandr1967 [171]

Answer:

Y' = (-2, 4\frac{2}{3})

Step-by-step explanation:

Given

Y = (-3,7)

Scale\ Factor = (\frac{2}{3}x,\frac{2}{3}y)

Required

Determine Y'

Y' can be solved by multiplying the scale factor by Y

i.e.

Y' = Scale\ Factor * Y

For, the x coordinates.

Y' = \frac{2}{3}x

Where

x = -3

Y' = \frac{2}{3} * -3

Y' = \frac{-6}{3}

Y = -2

For the y coordinates:

Y' = \frac{2}{3}y

Where

y = 7

Y' = \frac{2}{3} * 7

Y' = \frac{14}{3}

Y' = 4\frac{2}{3}

Hence:

Y' = (-2, 4\frac{2}{3})

3 0
3 years ago
Solve the system of equations -x+ 2y = –11 and 5x – 8y = 39 by<br> combining the equations.
Alchen [17]

Answer:

x=-5, y=-8. (-5, -8).

Step-by-step explanation:

-x+2y=-11

5x-8y=39

---------------

5(-x+2y)=5(-11)

5x-8y=39

---------------------

-5x+10y=-55

5x-8y=39

--------------------

2y=-16

y=-16/2

y=-8

-x+2(-8)=-11

-x-16=-11

-x=-11+16

-x=5

x=-5

3 0
2 years ago
How can you use models to find factor
Karo-lina-s [1.5K]
Yes, it depends on what kind of model
4 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
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