Wat is the solution showing work to y= 6x y= 5x+7

1 answer:

3 0

From what I recall, just set both the equations equal to each other

6x=5x+7

6x=5x+7
-5x -5x

1x=7

x=7

Then just plug in what you found.

y=6(7)
y=42

y=5(7)+7
y=35+7
y=42

42=42

Thus, you know your answer is correct.

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For the lines x=3t, y=1-2t, z=2-3t and x (3, 1, 4) +s(-9, 6, 9) (a) Show that the lines are parallel. (b) Calculate the distance

son4ous [18]

Answer:

Step-by-step explanation:

Given lines in parametric form

line $L_1$

$\frac{x}{3}=\frac{y-1}{-2} =\frac{z-2}{-3}$

direction vector of $L_1 v_1=$

Line $L_2$

direction vector of $L_2 v_2=$

therefore

$v_2=-3v_1$

thus lines are parallel.

(ii)distance between two lines is

$L_2$ is given by

$\frac{x-3}{-9}=\frac{y-1}{6} =\frac{z-4}{9}$ =s

$\frac{x-3}{-3}=\frac{y-1}{2} =\frac{z-4}{3}$ =3s

$\left | \frac{\begin{vmatrix}x_2-x_1 &y_2-y_1 &z_2-z_1 \\ a_1&b_1&c_1 \\ a_2&b_2&c_2\end{vmatrix}}{\sqrt{\left ( a_1b_2-a_2b_1 \right )^2+\left ( b_1c_2-b_2c_1 \right )^2+\left ( c_1a_2-c_2a_1 \right )^2}}\right |$