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postnew [5]
2 years ago
10

How much of a radioactive substance must be presented to decay to 80 grams in 12 years if the half-life of the substance is 7.6

years?
Mathematics
2 answers:
elena-s [515]2 years ago
8 0

Answer:

239 grams.

Step-by-step explanation:

Half life t(1/2) = ln 2 / k

So 7.6 = ln 2 / k

k = ln 2 / 7.6 = 0 0901204

N = No e^-kt

So after 12 years

80 = No / e^(-0.0901204*12)

No = 80 / e^(-0.0901204*12)

= 239.

max2010maxim [7]2 years ago
4 0

Answer:

Radioactive in half life is 51gram

Step-by-step explanation:

80grams:12years

X :7.6years

12x÷x=x

7.6×80÷12=51gram

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alisha [4.7K]
<h2>Answer:</h2>

\left(\frac{4^{21}}{5^6}\right)

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4 to the 21st over 5 to the 6th.

<h2>Step-by-step explanation:</h2>

First, we need to write our expression. Let's do it step by step:

<u>4 to the 7th:</u>

4^7

<u>5 squared:</u>

5^2

<u>4 to the 7th over 5 squared:</u>

\frac{4^7}{5^2}

<u>4 to the 7th over 5 squared all raised to the 3rd power:</u>

<u>\left(\frac{4^7}{5^2}\right)^3</u>

Using the law of exponents:

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