How much of a radioactive substance must be presented to decay to 80 grams in 12 years if the half-life of the substance is 7.6
years?
2 answers:
Answer:
239 grams.
Step-by-step explanation:
Half life t(1/2) = ln 2 / k
So 7.6 = ln 2 / k
k = ln 2 / 7.6 = 0 0901204
N = No e^-kt
So after 12 years
80 = No / e^(-0.0901204*12)
No = 80 / e^(-0.0901204*12)
= 239.
Answer:
Radioactive in half life is 51gram
Step-by-step explanation:
80grams:12years
X :7.6years
12x÷x=x
7.6×80÷12=51gram
You might be interested in
Answer:
Oh I don't know what that is but good luck
Answer:
cool
Step-by-step explanation:
A = pi(r)^2
diameter is 18in, so radius is 9in
= pi(9)^2
A = 254.469 (round is needed)
The answer should be c hope this helps
Answer:
do you have pictures that I can see
