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schepotkina [342]
3 years ago
5

Arnold had three pieces of different colored strings that are all the same length. Arnold cut the blue string into 2 equal size

lengths. he cut the red string into 3 equal-size length, and the green string into 6 equal-size. He needs to cut the strings so each color has the same number of equal-size lengths. What is the least number of equal size lengths each color string could have?
Mathematics
2 answers:
irina [24]3 years ago
4 0
6
he cut the blue string in half.
he cut the red string in thirds
he cut the green string in sixths.

2(half) goes into 6
3(thirds) go into 6
the sixths stay the same
Grace [21]3 years ago
3 0

Answer:

Least number of equal length = 6

Step-by-step explanation:

Given : Arnold had three pieces of different colored strings that are all the same length. Arnold cut the string

Blue- 2 equal size length

Red- 3 equal size length

Green- 6 equal size length

To find : The least number of equal size lengths each color string could have

Solution :  To find the least number we find the least common multiples of 2,3,6 or L.C.M of 2,3,6

Multiple of 2 = 2,4,6,8....

Multiple of 3 = 3,6,9....

Multiple of 6 = 6,12,18....

So the least number of equal length is 6.

or   L.C.M of 2,3,6 = 6      

Therefore, 6 is the least number of equal size lengths each color string could have.

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cost before increase = 63.6 × 100/106

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7 0
3 years ago
The diameter of a circle is 6 m. Find its area in terms of pi
Pie
<h2><em>Answer:</em></h2><h2><em>9</em><em> </em><em>pi </em><em>m^</em><em>2</em></h2>

<em>Solution</em><em>,</em>

<em>Diameter</em><em>=</em><em>6</em><em> </em><em>m</em>

<em>Radius=</em><em> </em><em>6</em><em>/</em><em>2</em><em>=</em><em>3</em><em>m</em>

<em>Area </em><em>of </em><em>circle=</em><em> </em><em>pi </em><em>r </em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>pi </em><em>*</em><em>(</em><em>3</em><em>)</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>pi*</em><em>9</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em> </em><em>pi </em><em>metre^</em><em>2</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

7 0
3 years ago
Read 2 more answers
The length of a rectangle is twice its width. if the area of the rectangle is 128 ft2 , find its perimeter.
kupik [55]
Length(l)= 2w
Width(w)= w
Area(A) = l*w

A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft

length(l)= 2w
l=2(8)
l=16 ft

P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft

Answer:
The Perimeter of this rectangle is 48 feet.


Leave any questions you still have in the comments below please! Thank you! Hope this helped! :)
5 0
3 years ago
Please i'm so dumb subtract 52 feet 2 inches - 2 1/4
vaieri [72.5K]

If I understand correctly the answer is 49 feet 11 inches

8 0
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podryga [215]

Answer:

For sure 34

Step-by-step explanation:

the red lines are the same length to each letter just add those.

8 0
3 years ago
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