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schepotkina [342]
3 years ago
5

Arnold had three pieces of different colored strings that are all the same length. Arnold cut the blue string into 2 equal size

lengths. he cut the red string into 3 equal-size length, and the green string into 6 equal-size. He needs to cut the strings so each color has the same number of equal-size lengths. What is the least number of equal size lengths each color string could have?
Mathematics
2 answers:
irina [24]3 years ago
4 0
6
he cut the blue string in half.
he cut the red string in thirds
he cut the green string in sixths.

2(half) goes into 6
3(thirds) go into 6
the sixths stay the same
Grace [21]3 years ago
3 0

Answer:

Least number of equal length = 6

Step-by-step explanation:

Given : Arnold had three pieces of different colored strings that are all the same length. Arnold cut the string

Blue- 2 equal size length

Red- 3 equal size length

Green- 6 equal size length

To find : The least number of equal size lengths each color string could have

Solution :  To find the least number we find the least common multiples of 2,3,6 or L.C.M of 2,3,6

Multiple of 2 = 2,4,6,8....

Multiple of 3 = 3,6,9....

Multiple of 6 = 6,12,18....

So the least number of equal length is 6.

or   L.C.M of 2,3,6 = 6      

Therefore, 6 is the least number of equal size lengths each color string could have.

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If Layla gets paid $948 a slow week . The employees Marco gets paid $9 an hour ,Stephanie gets paid $10.50 an hour ,and Destiny
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3 years ago
What is the LCM of x^2+5 and x^2+10x+25?
avanturin [10]

Answer:

(x+5)²(x²+5)

Step-by-step explanation:

Given two functions x²+5 and x²+10x+25, to get their Lowest common factor, we need to to first factorize x²+10x+25

On factorising we have:

x²+5x+5x+25

= x(x+5) +5(x+5

= (x+5)(x+5)

= (x+5)²

The LCM can be calculated as thus

| x²+5, (x+5)²

x+5| x²+5, (x+5)

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The LCM will be the product of the three functions i.e

(x+5)²(x²+5)

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