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faltersainse [42]
3 years ago
15

Which of the following relations is a function? A.{ (-2, 4), (-1, 3), (5, 2), (1, 4) } B.{ (1, 7), (1, 8), (2, 7), (3, 8) } C.{

(2, 4), (4, 6), (4, 8), (6, 4) } D.{ (5, 7), (6, 3), (8, 6), (5, 4) }
Mathematics
1 answer:
siniylev [52]3 years ago
3 0
From the pairs of x,y, if the set has two "x" of the same value, that is, "x" repeats, or an x-repeat, then is NOT a function

so, the group that doesn't have any x-repeats, is a function, now let's check

\bf A.\{ (-2, 4), (-1, 3), (5, 2), (1, 4) \}\\\\
B.\{ (\boxed{1}, 7), (\boxed{1}, 8), (2, 7), (3, 8) \}\impliedby \textit{has one re}\textit{peat, no dice}\\\\
C.\{ (2, 4), (\boxed{4}, 6), (\boxed{4}, 8), (6, 4) \}\impliedby \textit{also has one re}\textit{peat, no dice}\\\\
D.\{ (\boxed{5}, 7), (6, 3), (8, 6), (\boxed{5}, 4) \}\impliedby \textit{same, has one re}\textit{peat, no dice}
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3 years ago
Don't be childish I will report thanks ​
Semenov [28]

Answer:

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5 0
2 years ago
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−4+8x)+3&gt;x−4?<br><br> x&gt;16<br><br> x&lt;−1<br><br> x&lt;−323<br><br> x&gt;433
pentagon [3]

Answer:

x > 4/33

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6 0
2 years ago
-5/6+ -5/6 please help me
ehidna [41]
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5 0
3 years ago
Read 2 more answers
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
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