Answer:
When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).
i.e A'(0, 1) is the image of point A after a reflection.
Hence, point A is reflected across the x-axis.
Step-by-step explanation:
When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.
In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).
Thus, the rule is:
P(x, y) → P'(x, -y)
Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).
i.e A'(0, 1) is the image of point A after a reflection.
Hence, point A is reflected across the x-axis.
Since they are equal to 90 degrees. (complimentary angles)
6x-11+7x+10= 90
Combine like terms.
13x-1= 90
Add one to both sides.
13x= 91
x= 7
Plug that into the b.
7(7)+10
49+10
59
I hope this helps!
~kaikers
Answer:
Not Sure Without Slope
Step-by-step explanation:
you could use the formula y-y1=m(x-x1)(point slope form) where m is the slope, y1 is the first y point and x1 is the first x point.
For example if a line has slope 3 and passes through the points (5, 6), then the formula you would solve is y-6=3(x-5) to find the equation of the line in slope-intercept form and you should know what to do with everything else.
La respuesta es 112, es una regla de tres simples
I’m not 100% sure but probably 16 weeks
