Shelayna has 3 times as many dolls.
3*10=30
Cate has 10.
30-10=20 <=== Shelayna has 20 more dolls than Cate.
I hope this helps!
~kaikers
Here is the equation:

You need to find f(3). To do that, substitute all the x's with 3:

The first thing you need to do is multiply 4 by 3. Multiply:

Here is your new equation:

To get your answer, you need to add 12 and 1. Add:

That means:

<em>If you have any questions, feel free to ask in the comments! :)</em>
Answer:
5.678 liters in 1.5 gallons and 4.542 for 1.2 gallons in liters
Answer:
Step-by-step explanation:
10y2 - 17y + 12 = y + 16
10y2 - 17y + 12 - 16 = y
10y2 - 17y - 4 = y
10y2 -17y - y -4 = 0
10y2 -16y - 4 = 0
Now put formula
x = -b +- (square root) b2 - 4ac
2a
a = 10 b= -16 c= -4
y = -(-16) +- (square root) -16 - 4 (10) (-4)
2(10)
y = 16 +- (square root) -16 - 400
20
y = 16 +- (square root) -416
20
y = 16 +- 20.396
20
Now this +- is the plus minus thingy in which two answers come
The first we will do is +
16 + 20.396 16 - 20.396
20 20
= 1.8198 = -0.2198
Answer:
The circulation of the field f(x) over curve C is Zero
Step-by-step explanation:
The function
and curve C is ellipse of equation

Theory: Stokes Theorem is given by:

Where, Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Also, f(x) = (F1,F2,F3)

Using Stokes Theorem,
Surface is given by g(x) = 
Therefore, tex]\hat{N} = grad(g(x))[/tex]


Now, 
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5CF1%26F2%26F3%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = ![\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Chat%7Bi%7D%26%5Chat%7Bj%7D%26%5Chat%7Bk%7D%5C%5C%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82x%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82y%7D%20%26%5Cfrac%7B%E2%88%82%7D%7B%E2%88%82z%7D%20%5C%5Cx%5E%7B2%7D%264x%26z%5E%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Curl f(x) = (0,0,4)
Putting all values in Stokes Theorem,



I=0
Thus, The circulation of the field f(x) over curve C is Zero