Answer:
35/49/50
Step-by-step explanation:
3.5/7.8/4.9=50
Answer:
A.
Step-by-step explanation:
so, the equation is
h(t) = -t² + 7t
so, we need to find the solutions for t (the time when the ball is exactly 10 ft in the air). there had to be 2 solutions, as the ball first goes up passing the 10 ft height, and then comes back down again, passing the 10 ft mark a second time. and between these 2 times the ball is higher (but not equal, so, we can only use < or > as inequality signs) than 10 ft.
10 = -t² + 7t
-t² + 7t - 10 = 0
the generation solution to a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = t
a = -1
b = 7
c = -10
t = (-7 ± sqrt(7² - 4×-1×-10))/(2×-1) =
= (-7 ± sqrt(49 - 40))/-2 = (-7 ± sqrt(9))/-2
t1 = (-7 + 3)/-2 = -4/-2 = 2 seconds
t2 = (-7 - 3)/-2 = -10/-2 = 5 seconds
so, between 2 and 5 seconds airtime the ball is higher than 10 ft.
and remember : HIGHER THAN.
so, we cannot use any equality (like <= or >=).
t must be higher than 2 and lower than 5 :
2 < t < 5
<h2>
The length of the yard was 563 yards.</h2>
Step-by-step explanation:
Given,
The area of the yard = 6,756 square yards and
The width of the yard (b) = 12 yards
To find, the length of the yard (l) = ?
We know that,
Area of the rectangle = Length(l) × Breadth(b)
⇒ l × 12 = 6,756
⇒ l =
⇒ l = 563 yards
Thus, the length of the yard was 563 yards.
15 + 20 + 10 = 45 I think hope it helps
Answer:
904.78
Step-by-step explanation:
V = 4/3 pi r^2
4/3 pi 6^2
904.78
