Question

What is the radical form of x with the exponent of 1.5

Answer 1

Answer:

$\sqrt[2]{x^3}$

Step-by-step explanation

First thing you should do is change the decimal into a fraction,

In this problem you have one whole plus a half. So you can rewrite that into $1\frac{1}{2}$. Which is the same thing as $\frac{3}{2}$

Why  $\frac{3}{2}$ ?

Because one whole number is the same as $\frac{1}{1},\frac{2}{2},\frac{3}{3},\frac{4}{4},\frac{5}{5}$ since all of those numbers divided by themselves equals to one. You'll take $\frac{2}{2}$ and add it with $\frac{1}{2}$.

 

Now since we have $x^\frac{3}{2}$, THE DENOMINATOR WILL BECOME THE SQUARE ROOTS NUMBER, AND THE NUMERATOR WILL BE EXPONENT.

So it becomes, $\sqrt[2]{x^3}$