Answer:
![144ft^2](https://tex.z-dn.net/?f=144ft%5E2)
Step-by-step explanation:
For this problem, we can use the formula for the area of a kite.
![A=\frac{pq}{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7Bpq%7D%7B2%7D)
Where p and q are the diagonals.
Since line AE starts at the edge of the kite and ends at the center, we can multiply its value by 2 to find the value of the p diagonal.
![6*2=12](https://tex.z-dn.net/?f=6%2A2%3D12)
So diagonal p is 12ft.
Now we can find the value of the q diagonal, which will be adding BE and DE.
![9+15=24](https://tex.z-dn.net/?f=9%2B15%3D24)
So diagonal q is 24ft.
Let's plug them into the area formula I mentioned earlier.
![A=\frac{12*24}{2} \\ \\ A=\frac{288}{2} \\ \\ A=144](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B12%2A24%7D%7B2%7D%20%5C%5C%20%5C%5C%20A%3D%5Cfrac%7B288%7D%7B2%7D%20%5C%5C%20%5C%5C%20A%3D144)