The answer would be b
Mean Absolute Deviation Worksheet 1
1 answer:
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Answer:
Shortest distance=|AC|/.
Kindly find the attached for the figure
Step-by-step explanation:
This problem can be addressed using right-angled,
Let have right angle triangle with the shortest distance=hypotenuse;
hypotenuse=|AC|
using pythagoras theorem, we have
|AC|^2=|AB|^2+|BC|^2
Let |AB|=|BC|
|AC|^2=2|AB|^2
|AB|=|AC|/
Shortest distance=|AC|/
