<span> x2 – 12x + 36 = 4
(x - 6)^2 = 2^2
x - 6 = 2
x = 8
-(x - 6) = 2
-x + 6 = 2
-x = -4
x = 4
answer
</span><span>C. {4, 8}</span>
Answer: 3
Step-by-step explanation:
Given
The dimension of the small block is
The Volume of the cube having unit length is
The number of blocks that can be in the unit cube is the division of the volume of the unit cube and block.
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:
4
Step-by-step explanation:
E=mc^2 if m=3 and c=6
e=3(6^2)
e=3(36)
e=108
