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Iteru [2.4K]
3 years ago
8

The function f is defined on the set of real numbers f(x) equals to 4x + 3 find f^-1(x) and hence determine f^-1(½)

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

The answer and solution are in the picture above

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Simplify (6²)4. <br>how to get the answer​
Anna71 [15]

Answer:

144

Step-by-step explanation:

6^2 = 6x6 = 36

36 x 4 = 144

7 0
2 years ago
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Use slope formula,m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction, to find the slope of a line that passes throug
Leya [2.2K]

Answer:

a. Slope is -2/7

b. b = 1

c. y = 2x + 1

Hope this helps :)

Step-by-step explanation:

7 0
3 years ago
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The line passes through (2,1) and (6,7)
Ilya [14]
............y=3/2x-2
3 0
3 years ago
When calculating the effective rate of a loan, which statement or statements must be true if n is greater than 1? I. The length
Fed [463]

When calculating the loan's effective rate, the most accurate statement is that the effective rate will exceed the nominal rate.

<h3>Effective Annual Rate:</h3>

The interest rate for the entire year is known as the effective annual rate (EAR). Interest charges are incurred when a company uses debt or capital leases to fund its operations.

Interest is reported on the income statement, but it can also be generated on an investment or paid on a loan over time due to compounding interest.

It is frequently larger than the marginal rate and is used to compare various financial products with different compounding periods, such as weekly, monthly, and yearly.

The effective yearly interest rate rises over time as the number of compounding periods increases.

Therefore, the correct option is A.

Learn more about the loans here:

brainly.com/question/2405320

8 0
3 years ago
Read 2 more answers
Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
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