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3 years ago

Is 6 2/3 bigger then 6 12/15

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

6 0

Answer:

6 2/3 is greater

Step-by-step explanation:

SCORPION-xisa [38]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

think about it

6 1/2 equals to 2/20 or 1/10

6 12/15 equals 12/102

so the answer is yes

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What is 2.3 less than 5

djyliett [7]

Answer:

5-2.3=2.7

Step-by-step explanation:

put into an equation format, 2.3 less than 5 is 5-2.3

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3 years ago

Identify the slope and y-intercept of the graph of the equation. y = 5/3x -2

frez [133]

Answer:

The slope is 5/3 and the y-int is -2

Step-by-step explanation:

Step 1: Identify the slope

The slope is the number attached to the x. Therefore, the slope is 5/3.

Step 2: Identify the y-int

The y-int is the number that is after the x

y = mx + b

Therefore, the y-int is -2

Answer: The slope is 5/3 and the y-int is -2

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3 years ago

A bike race takes place over a 3 mile course. How many feet is it?

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Answer:

Step-by-step explanation:

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3 years ago

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Factor numerical expressions using the dist

vfiekz [6]

Step-by-step explanation:

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2 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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3 years ago

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