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3 years ago

Find the mean and range. 26 19 23 39 31 34 23 25

2 answers:

7 0

Range: largest number minus the smallest number
39 - 19 = 20
your range is 20

Mean: add all of the numbers and divide by the amount of numbers there are.

26+19+23+39+31+34+23+25= 220
220/8 = 27.5

your mean is 27.5

hope this helps

Aneli [31]3 years ago

5 0

QUESTION 1

The given data set is;

$26,19,23,39,31,34,23,25$

The mean can be found using the formula;

$\bar X =\frac{\sum x}{n}$

$\Rightarrow \bar X =\frac{26+19+23+39+31+34+23+25}{8}$

$\Rightarrow \bar X =\frac{220}{8}$

$\Rightarrow \bar X =27.5$

QUESTION 2

To find the range we may sort the data to obtain;

$19,23,23,25,26,31,34,39$

We see that the maximum value is 39 and least value is 19

The range is the largest value minus the least value.

This implies that;

$Range=39-19$

$\Rightarrow Range=20$

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3 years ago

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

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We are given

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$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

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$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

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